Question

Виконати Множення
(x+6)(3+x)=
(a+2)(4-a)=
(3y²-1)(y+5)=
(8y-4)(y-3)=
(5y³+2)(y²+1)=
(11-2y)(6-y+2y²)=
СРОЧНО!!

Answer 1

Ответ:

1. \((x+6)(3+x) = x(3+x) + 6(3+x) = 3x + x^2 + 18 + 6x = x^2 + 9x + 18\)

2. \((a+2)(4-a) = a(4-a) + 2(4-a) = 4 - a^2 + 8 - 2a = -a^2 - 2a + 12\)

3. \((3y²-1)(y+5) = 3y²(y+5) - 1(y+5) = 3y³ + 15y² - y - 5\)

4. \((8y-4)(y-3) = 8y(y-3) - 4(y-3) = 8y² - 24y - 4y + 12 = 8y² - 28y + 12\)

5. \((5y³+2)(y²+1) = 5y³(y²+1) + 2(y²+1) = 5y⁵ + 5y³ + 2y² + 2\)

6. \((11-2y)(6-y+2y²) = 11(6-y+2y²) - 2y(6-y+2y²) = 66 - 11y + 22y² - 12y + 2y² = 22y² - 23y + 66\)