Предмет: Алгебра, автор: aukrainec982

ПОЖАЛУЙСТА! ПОМОГИТЕ!!!

тупой задание, но я не умнее. Половину решил, но дальше затупил

\frac{(m-5n)^{2}*5}{0,2m^{2}-5n^{2} }

Ответы

Автор ответа: Ivan19074
1

Ответ:

\frac{25(m-5n)}{m+5n}

Объяснение:

Умножим всё на 5 и разложим на множители:

\frac{(m-5n)^2*5}{0.2m^2-5n^2}=\frac{25(m-5n)^2}{m^2-25n^2}=\frac{25(m-5n)^2}{(m-5n)(m+5n)}=\frac{25(m-5n)}{m+5n}

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