Question

синА= 5/13.Найдите  tg a

Answer 1

tgA=sinA/корень(1-sinA в квадрате)=(5/13)/корень(1-25/169)=(5/13)/(12/13)=5/12

Answer 2

спасибо большое))

Answer 3

пож-та

Answer 4

tga=sina/√1-sin²a=5/13 : √(1-25/169)=5/13: 12/13=5/12