Question

2sin π/2 -3cos(-π/3)

Answer 1

Ответ:

\[2\sin\left(\frac{\pi}{2}\right) - 3\cos\left(-\frac{\pi}{3}\right)\]

Recall that \(\sin\left(\frac{\pi}{2}\right) = 1\) and \(\cos\left(-\frac{\pi}{3}\right) = \frac{1}{2}\). Substituting these values:

\[2 \cdot 1 - 3 \cdot \frac{1}{2} = 2 - \frac{3}{2} = \frac{1}{2}\]

So, \(2\sin\left(\frac{\pi}{2}\right) - 3\cos\left(-\frac{\pi}{3}\right) = \frac{1}{2}\).