Question

(x+1)(x-1)-x(x-4)=0 помоги
те решить

Answer 1

$\displaystyle\bf\\(x+1)(x-1)-x(x-4)=0\\\\x^{2} -1-x^{2} +4x=0\\\\4x-1=0\\\\4x=1\\\\\boxed{x=0,25}$

Answer 2

X^2-1-x^2+4x=0
4x-1=0
4x=1
x=1/4