Question

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Answer 1

$\displaystyle\bf\\\frac{x^{2} +5x}{x^{2} -4}:\frac{x^{2}+10x+25 }{x+2} \cdot\frac{x+5}{x} =\\\\\\=\frac{x\cdot(x+5)}{(x-2)(x+2)}:\frac{(x+5)^{2} }{x+2} \cdot\frac{x+5}{x} =\\\\\\=\frac{x\cdot(x+5)}{(x-2)(x+2)}\cdot\frac{x+2}{(x+5)^{2} }\cdot\frac{x+5}{x} =\\\\\\=\frac{1}{x-2}$