155. Теңдеуді шешіңдер:
1) (-3 + x)x = 0;
3) (-x-2,5)(-2x) = 0;
5) |x - 1| · (|x| - 1) = 0;
7) (x + 1)(x − 2) = 0;
9) (-x + 1)(-x + 1) = 0;
2) (4 + 2x)(1-3x) = 0;
4) x + 1)(x + 1) = 0;
6) --x (x - 2) = 0;
8) |x-1|x - 3) = 0;
10) (--x+ 2)(3-x) = 0.
Помогите прошу
Ответы
Sure, I can help you solve these equations. Here are the solutions:
1) (-3 + x)x = 0
This equation can be solved by setting each factor to zero:
-3 + x = 0
x = 0
Therefore, the solutions are x = 3 and x = 0.
2) (4 + 2x)(1-3x) = 0
This equation can be solved by setting each factor to zero:
4 + 2x = 0
x = -2
1 - 3x = 0
x = 1/3
Therefore, the solutions are x = -2 and x = 1/3.
3) (-x-2.5)(-2x) = 0
This equation can be solved by setting each factor to zero:
-x - 2.5 = 0
x = -2.5
-2x = 0
x = 0
Therefore, the solutions are x = -2.5 and x = 0.
4) (x + 1)(x + 1) = 0
This equation can be solved by setting each factor to zero:
x + 1 = 0
x = -1
Therefore, the solution is x = -1.
5) |x - 1| · (|x| - 1) = 0
This equation can be solved by considering two cases:
Case 1: x - 1 = 0
x = 1
Case 2: |x| - 1 = 0
x = 1 or x = -1
Therefore, the solutions are x = 1 and x = -1.
6) --x (x - 2) = 0
This equation can be solved by setting each factor to zero:
--x = 0
x = 0
x - 2 = 0
x = 2
Therefore, the solutions are x = 0 and x = 2.
7) (x + 1)(x − 2) = 0
This equation can be solved by setting each factor to zero:
x + 1 = 0
x = -1
x - 2 = 0
x = 2
Therefore, the solutions are x = -1 and x = 2.
8) |x-1|x - 3) = 0
This equation can be solved by considering two cases:
Case 1: x - 1 = 0
x = 1
Case 2: x - 3 = 0
x = 3
Therefore, the solutions are x = 1 and x = 3.
9) (-x + 1)(-x + 1) = 0
This equation can be solved by setting each factor to zero:
-x + 1 = 0
x = 1
Therefore, the solution is x = 1.
10) (--x+ 2)(3-x) = 0
This equation can be solved by setting each factor to zero:
--x + 2 = 0
x = -2
3 - x = 0
x = 3
Therefore, the solutions are x = -2 and x = 3.