Предмет: Физика, автор: BmwFan232

Тело движется нейной скоростью бом Опредилите ра 60 м/с по окружности с ли- диус окружности если период вращения равно 2 с.(0=3)

Ответы

Автор ответа: vdovinaannastasia

0

Объяснение:

вот наверное правильно

Приложения:

Автор ответа: t0663896707

0

Відповідь:

Для того чтобы определить радиус окружности, по которой движется тело со скоростью

60

м/с

60м/с и периодом вращения

2

с

2с, воспользуемся формулой для линейной скорости вращения:

Линейная скорость вращения

�

v связана с радиусом

�

r и периодом вращения

�

T следующим образом:

�

=

2

�

�

�

,

v=

T

2πr

,

где

�

v - линейная скорость,

�

r - радиус окружности,

�

T - период вращения.

Мы знаем, что

�

=

60

м/с

v=60м/с и

�

=

2

с

T=2с. Подставим это в формулу и решим ее относительно радиуса

�

r:

60

=

2

�

�

2

.

60=

2

2πr

.

У нас

�

=

2

с

T=2с, поэтому:

60

=

�

�

.

60=πr.

Теперь найдем значение радиуса:

�

=

60

�

≈

19.1

м

.

r=

π

60

≈19.1м.

Таким образом, радиус окружности, по которой движется тело со скоростью

60

м/с

60м/с при периоде вращения

2

с

2с, составляет примерно

19.1

м

19.1м.

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