Question

Розв'яжіть рівняння,будь ласка терміново

Answer 1

$\frac{4x - 1}{x + 3} - \frac{3x - 2}{x - 1} = 1 \\ \frac{4x - 1}{x + 3} - \frac{3x - 2}{x - 1} = 1 \\ x≠ - 3 \\ x≠1 \\ \frac{(x - 1) \times (4x - 1) - (x + 3) \times (3x - 2)}{(x + 3) \times (x - 1)} = 1 \\ \frac{4 {x}^{2} - x - 4x + 1 - (3 {x}^{2} - 2x + 9x - 6) }{(x + 3) \times (x - 1)} = 1 \\ \frac{4 {x}^{2} - x - 4x + 1 - (3 {x}^{2} + 7x - 6) }{(x + 3) \times (x - 1)} = 1 \\ \frac{4 {x}^{2} - x - 4x + 1 - 3 {x}^{2} - 7x + 6 }{(x + 3) \times (x - 1)} = 1 \\ \frac{ {x}^{2} - 12x + 7 }{(x + 3) \times (x - 1)} = 1 \\ {x}^{2} - 12x + 7 = (x + 3) \times (x - 1) \\ {x}^{2} - 12x + 7 = {x}^{2} - x + 3x - 3 \\ - 12x + 7 = - x + 3x - 3 \\ - 12x + 7 = 2x - 3 \\ - 12x - 2x = - 3 - 7 \\ - 14x = - 10 \\ x = \frac{5}{7} \\ x ≠ - 3 \\ x≠1 \\ x = \frac{5}{7}$