Предмет: Химия, автор: dаriа17

Какой объём хлороводорода (при нормальных условиях) надо растворить в воде,чтобы образовавшееся раствор смог полностью прорекларировать с 0,2 моль магния

Ответы

Автор ответа: nikolaygr

1

Відповідь:

дано:

n(Mg)=0,2моль

V(HCI)-?

Mg+2HCI=MgCI2+H2

n(Mg):n(HCI)=1:2

n(HCI)=0,2*2=0,4моль

V(HCI)=22,4*0,4=8,96л

Пояснення:

dаriа17: Благодарю

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