Предмет: Алгебра, автор: sofia142314

Розв'яжіть систему {12х+6-3(5х+4)≤24 {(х+5)²≥х²+6х+65

Ответы

Автор ответа: timofei9009900

1

Ответ:

$1. \: 12x + 6 - 15x - 12 \leqslant 24 \\ - 3x \leqslant 30 \\ x \geqslant - 10$

${(x + 5)}^{2} \geqslant {x}^{2} + 6x + 65 \\ {x}^{2} + 10x + 25 - {x}^{2} - 6 x- 65 \geqslant 0 \\ 4x \geqslant 40 \\ x \geqslant 10$

Объяснение:

ответ х больше или равно 10

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