Question

2sin ($pi \ 4$ - x)+√3=0

Answer 1

$2sin(frac{pi}{4}-x)+sqrt{3}=0$
$sin(frac{pi}{4}-x)=-frac{sqrt{3}}{2}$
$frac{pi}{4}-x=(-1)^k*arcsin(-frac{sqrt{3}}{2})+pi*k$
$-frac{pi}{4}+x=(-1)^k*frac{pi}{3}-pi*k$
$x=frac{pi}{4}+(-1)^l*frac{pi}{3}+pi*l$
l є Z