Question

sin L, если cos L/2 - sin L/2 = 3/4

Answer 1

$(cosfrac{ alpha }{2}-sinfrac{ alpha }{2})^2=cos^2frac{ alpha }{2}+sin^2frac{ alpha } {2}-2sinfrac{ alpha }{2}cdot cosfrac{ alpha }{2}=1-sin alpha =(frac{3}{4})^2\\sin alpha =1-frac{9}{16}=frac{7}{16}$