Предмет: Физика, автор: vitalijskripcov7

Знайдіть час і місце зустрічі двох тіл, рух яких описується рівняннями: x1=2 + 4t x2=4-2t

Ответы

Автор ответа: anagrisanova12

Ответ:

$2 + 4t = 4 - 2t \\ 6t = 2 \\ t = 2 \div 6 = 0.3c \\ \\ x = 2 + 4 \times 0.3 = 3.2m$

Объяснение:

час через який зустрінуться ≈ 0,3 с

координата (x) ≈ 3,2

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