Question

поможіть срочно даю 70 балов!!!!!​

Answer 1

Ответ:

$= {y}^{2} ( {y}^{2} - 3y + 1) - 2 {y}^{2} ( {y }^{2} - 3y + 1) + {y}^{2} ( {y}^{2} + 3y - 1) = ({y}^{2} - 3y + 1)( {y}^{2} - 2 {y}^{2} ) + {y}^{2} ( {y}^{2} + 3y - 1)$

$- {y}^{2} ( {y}^{2} - 3y + 1) + {y}^{2} ( {y}^{2} + 3y - 1) = - {y}^{2} - {y}^{2} =6 {y}^{3} - 2 {y}^{2}$

$= 2 {y}^{2} (3y - 1) = 2 \times { (\frac{4}{3} )}^{2} (3 \times \frac{4}{3} - 1) =$

$\frac{32}{9} \times 3 = \frac{32}{3}$