Question

AL+H2SO4 -->
FeCL3 +NaOH -->
Na + O2 -->
Fe + CuCL -->
Даю 40 б.

Answer 1

1. AL + H2SO4 → Al2(SO4)3 + H2

2. FeCl3 + 3NaOH - Fe(OH)3 + 3NaCl

3. 2Na 2Na20

4. Fe + 2CuCI2 2FeCl3 + 2Cu

Answer 2

Ответ:

Объяснение:

1. 2Al + 3H2SO4 → 3H2 + 2Al2(SO4)3

2. FeCl3 + 3NaOH -> Fe(OH)3 + 3NaCl

3. 4 Na + O2 → 2 Na2O

4. Fe + 2CuCl₂ → 2Cu + FeCl₂