Question

19600-√32*√2-(√129)²-√108/√3+√(-38)²=
пошаговое решение ​

Answer 1

$\displaystyle\bf\\19600-\sqrt{32} \cdot\sqrt{2} -(\sqrt{129} )^{2} -\frac{\sqrt{108} }{\sqrt{3} } +\sqrt{(-38)^{2} } =\\\\\\=19600-\sqrt{32\cdot 2} -129-\sqrt{\frac{108}{3} } +38=\\\\\\=\underbrace{(19600-129+38)}_{19509}-\sqrt{64} -\sqrt{36} =19509-8-6=19495$