Question

5r – (r+ 1) = 4(r – 2). 4
даю 70балов фастом пж​

Answer 1

$\displaystyle\bf\\5r-(r+1)=4(r-2)\cdot 4\\\\5r-r-1=16r-32\\\\4r-1=16r-32\\\\4r-16r=1-32\\\\-12r=-31\\\\r=-31:(-12)=2\frac{7}{12}$

Answer 2

Ответ:

2 7/12

Объяснение:

5r - (r + 1) = 4(r - 2) * 4

5r - (r + 1) = 16(r - 2)

5r - r - 1 = 16r - 32

4r - 1 = 16r - 32

4r - 16r = -32 + 1

-12r = -31

r = -31 : (-12)

r = 31/12

r = 2 7/12