Question

2ab * 3c ^ 2 * d * (2c * d ^ 2)/(9a*beta) / ((a ^ 2 * b)/(6 ^ 3 * d)) =

Answer 1

Ответ:

2ab * 3cd * 2cd/(9ab) / (a^2b/(6^3d))

(сократим 2ab и 3cd)

= 2cd * 1/(3ab) * (6^3/a^2)d

= (2cd/3ab) * (216/a^2) * d

(упростим 216/a^2 как 8/a)

= (8cd/ab)d