Question

(a²-a) × (a+1) a=2
Пжжж​

Answer 1

$\displaystyle\bf\\(a^{2} -a)\cdot(a+1)\cdot a=2\\\\(a^{2} -a)\cdot(a^{2} +a)=2\\\\(a^{2} )^{2} -a^{2} -2=0\\\\a^{4} -a^{2} -2=0\\\\a^{2} =m \ \ ; \ \ m\geq 0\\\\m^{2} -m-2=0\\\\D=(-1)^{2} -4\cdot (-2)=1+8=9=3^{2} \\\\\\m_{1} =\frac{1+3}{2} =\frac{4}{2} =2\\\\\\m_{2} =\frac{1-3}{2} =\frac{-2}{2} =-1 \ < 0 \ - \ ne \ podxodit\\\\\\a^{2} =2\\\\\boxed{a_{1} =-\sqrt{2} \ \ \ ; \ \ \ a_{2} =\sqrt{2} }$