Question

Решите: x^3-6x^2+12x-8=0...если можно с объяснением :)

Answer 1

x³-6x²+12x-8=0

x³-8 - 6x²+12x=0

x³- 2³ - 6x²+12x=0

(x- 2)(х²+2х+4) - 6x(х -2)=0

(x- 2)(х²+2х+4-6х) =0

(x- 2)(х²-4х+4) = 0

(x- 2)(х²-4х+ 2²) = 0

(x- 2)(х -2)² = 0

(x- 2)³ = 0

х-2=0

х=2