Question

помогте пж срочно
а)(x+1)∧7＝-1
б)(2х-5)∧2+1=0
в) х∧6-1＝0

Answer 1

Ответ:

a)

$(x + 1) {}^{7} = - 1 \\ \sqrt[7]{(x + 1) {}^{7} } = \sqrt[7]{ - 1} \\ x + 1 = - 1 \\ x = - 1 - 1 \\ x = - 2$

б)

$(2x - 5) {}^{2} + 1 = 0 \\ 4 {x}^{2} - 20x + 25 + 1 = 0 \\ 4 {x}^{2} - 20x + 26 = 0 \\ 2 {x}^{2} - 10x + 18 = 0 \\ D = {b}^{2} - 4ac \\ D = ( - 10) {}^{2} - 4 \times 2 \times 13 = 100 - 104 = - 4 \\ ∅$

в)

${x}^{6} - 1 = 0 \\ {x}^{6} = 1 \\ \sqrt[6]{1} = x \\ x = ±1$