Question

(-2 1/3)²+(1/2)³-(3/19)⁰+(-1)¹²=
Помогите!!!

Answer 1

$( - 2 \frac{1}{3} ) {}^{2} + ( \frac{1}{2} ) {}^{3} - ( \frac{3}{19} ) {}^{0} + ( - 1) {}^{12} = ( - 2 \frac{1}{3} ) {}^{2} + ( \frac{1}{2} ) {}^{3} - 1 + 1 = ( - 2 \frac{1}{3} ) {}^{2} + \frac{1}{8} = ( - \frac{7}{3} ) {}^{2} + \frac{1}{8} = \frac{49}{9} + \frac{1}{8} = \frac{401}{72} = 5 \frac{41}{72}$