Question

Допоможіть будь ласка​

Answer 1

Ответ:

$\sqrt{x} + \sqrt[4]{x} = 2 \\ \sqrt{x} + \sqrt[4]{x} - 2 = 0 \\ t^{2} + t - 2 = 0 \\ t = - 2 \\ t = 1 \\ \sqrt[4]{x} = - 2 \\ ∅ \\ \sqrt[4]{x} = 1 \\ x = 1$

$\sqrt{x} - 3 \sqrt[4]{x} + 2 = 0 \\ t^{2} - 3 t + 2 = 0 \\ (t - 1)(t - 2) = 0 \\ t = 1 \\ t = 2 \\ \sqrt[4]{x} = 1 \\ x = 1 \\ \sqrt[4]{x} = 2 \\ x = 16$