Question

5/48+3/8+1/48=
(7/15+2/9)-2/15=​
17/27-(5/27+1/6)=


11-х=1/16

Answer 1

Ответ:

1)

$\frac{1}{2}$

2

$\frac{5}{9}$

3)

$\frac{5}{18}$

Пошаговое объяснение:

1)

$\frac{5}{48} + \frac{3}{8} + \frac{1}{48} = \\ = \frac{5}{48} + \frac{6 \times 3}{6 \times 8} + \frac{1}{48} = \\ = \frac{5}{48} + \frac{18}{48} + \frac{1}{48} = \\ = \frac{5 + 18 + 1}{48} = \\ = \frac{24}{48} = \frac{1}{2}$

2)

$( \frac{7}{15} + \frac{2}{9} ) - \frac{2}{15} = \\ = ( \frac{3 \times 7}{3 \times 15} + \frac{5 \times 2}{5 \times 9} ) - \frac{3 \times 2}{3 \times 15} = \\ = ( \frac{21}{45} + \frac{10}{45} ) - \frac{6}{45} = \\ = \frac{21}{45} + \frac{10}{45} - \frac{6}{45} = \\ = \frac{21 + 10 - 6}{45} = \\ = \frac{25}{45} = \frac{5 \times 5}{5 \times 9} = \\ = \frac{5}{9}$

3)

$\frac{17}{27} - ( \frac{5}{27} + \frac{1}{6} ) = \\ = \frac{2 \times 17}{2 \times 27} - ( \frac{2 \times 5}{2 \times 27} + \frac{9 \times 1}{9 \times 6} ) = \\ = \frac{34}{54} - ( \frac{10}{54} + \frac{9}{54} ) = \\ = \frac{34}{54} - \frac{10}{54} - \frac{9}{54} = \\ = \frac{34 - 10 - 9}{54} = \\ = \frac{15}{54} = \frac{3 \times 5}{3 \times 18} = \\ = \frac{5}{18}$