Question

Доведіть тотожність срочно даю 45 балов​

Answer 1

Ответ:

$\frac{m-2}{6-m}-\frac{m-3}{m+6}+\frac{2m(m-2)}{m^2-36}=\frac{1}{m+6}$

Объяснение:

$\frac{m-2}{6-m}-\frac{m-3}{m+6}+\frac{2m(m-2)}{m^2-36}=\\\\\frac{2-m}{m-6}-\frac{m-3}{m+6}+\frac{2m(m-2)}{(m-6)(m+6)}=\\\\\frac{(2-m)(m+6)}{(m-6)(m+6)}-\frac{(m-3)(m-6)}{(m-6)(m+6)}+\frac{2m^2-4m}{(m-6)(m+6)}=\\\\\frac{2m+12-m^2-6m}-\frac{m^2-6m-3m+18}{(m-6)(m+6)}+\frac{2m^2-4m}{(m-6)(m+6)}=\\\\\frac{2m+12-m^2-6m-m^2+6m+3m-18+2m^2-4m}{(m-6)(m+6)}=\\\\\frac{m-6}{(m-6)(m+6)}=\\\\\frac{1}{m+6}$