Question

c³-2c²+3c-4-(c³-3c²-5), якщо c=2

Answer 1

Ответ:

c = 11

Объяснение:

C³-2c²+3c-4-(c³-3c²-5)

= 2³ - 2(2)² + 3(2) - 4 - (2³ - 3(2)² - 5)

= 8 - 8 + 6 - 4 - (8 - 12 - 5)

= 8 - 8 + 6 - 4 - 8 + 12 + 5

= 11

Answer 2

Ответ:

${c}^{3} - 2 {c}^{2} + 3c - 4 - ( {c}^{3} - 3 {c}^{2} - 5) = {c}^{3} - 2 {c}^{2} + 3c - 4 - {c}^{3} + 3 {c}^{2} + 5 = {c}^{2} + 3c + 1= 4 + 6 + 1 = 11$