Question

f(х)=(х-2)(х+3).Найти значение х, если f(х)= 0.

Answer 1

$\displaystyle\bf\\f(x)=(x-2)(x+3)\\\\f(x)=0\\\\(x-2)(x+3)=0\\\\\\\left[\begin{array}{ccc}x-2=0\\x+3=0\end{array}\right \ \ \ \Rightarrow \ \ \ \left[\begin{array}{ccc}x_{1} =2\\x_{2}=-3 \end{array}\right\\\\\\Otvet \ : \ 2 \ ; \ -3$