Question

Помогите пожалуйста

a) 3(x – 1) = 5(2x – 3) ; c) 3(2x + 1) = 5x + 2 – 2(x + 1) ;
b) 4(x – 5) = 3 – (x + 1) ; d) 8x – 3(x – 2) = 10 + 5(1 – 2x)

Answer 1

Ответ:

$1)3(x - 1) = 5(2x - 3) \\ 3x - 3 = 10x - 15 \\ 15 - 3 = x(10 - 3) \\ 12 = 7x \\ x = \frac{7}{12}$

$2)4(x - 5) = 3 - (x + 1) \\ 4x - 20 = 3 - x - 1 \\ 4x + x = 20 + 3 - 1 \\ 5x = 22 \\ x = \frac{22}{5} \\ x =4 \frac{2}{5} \\ x = 4.4$

$3)3(2x + 1) = 5x + 2 - 2(x + 1) \\ 6x + 3 = 5x + 2 - 2x - 2 \\ 6x - 5x + 2x = 2 - 2 - 3 \\ x = - 3$

$4)8x - 3(x - 2) = 10 + 5(1 - 2x) \\ 8x - 3x + 6 = 10 + 5 - 10x \\ 8x - 3x + 10x = 10 + 5 - 6 \\ 15x = 9 \\ x = \frac{9}{15} \\ x = \frac{3}{5} \\ x = 0.6$