Question

(6√3−3√2)×√3+√54
помогите срочно​

Answer 1

$(6\sqrt{3} -3\sqrt{2} )*\sqrt{3} +\sqrt{54} =6\sqrt{3}*\sqrt{3}-3\sqrt{2}*\sqrt{3}+\sqrt{54} =$

$6\sqrt{3^{2} }-3\sqrt{6}+\sqrt{54}=6*3- 3\sqrt{6}+ \sqrt{54}=18-\sqrt{6*9}+ \sqrt{54}=$

$18-\sqrt{54} +\sqrt{54} =18$

Ответ: 18