Question

89 Pritaikykite daugybos skirstomumo dėsnį sudėties atžvilgiu ir apskaičiuokite: a) 7. (6 + 4); d) 11 (7+ 100); b) 4. (15 + 7); e) 20 (90+30); c) 5. (80 + 9); f) 4 (225 + 325).​

Answer 1

$a) 7 \cdot (6 + 4) = 7 \cdot 6 + 7 \cdot 4 = 42 + 28 = 70 \\ b) 4 \cdot (15 + 7) = 4 \cdot 15 + 4 \cdot 7 = 60 + 28 = 88 \\ c) 5 \cdot (80 + 9) = 5 \cdot 80 + 5 \cdot 9 = 400 + 45 = 445 \\ d) 11 \cdot (7+100) = 11 \cdot 7 + 11 \cdot 100 =77+1100=1177 \\ e) 20 \cdot (90+30) =20 \cdot90+20\cdot30=1800+600=2400 \\ f) 4 \cdot (225+325)=4\cdot225+4\cdot325=900+1300=2200$