Question

1 вариант (x - 1)×(x2 + 2x - 1). (6x-2a)×(4-3x) = (2a²b + 4ab²) : 2a​

Answer 1

Ответ:

$(x - 1)( {x}^{2} + 2x - 1) = {x}^{3} + 2 {x}^{2} - x - {x}^{2} - x + 1 = {x}^{3} - {x}^{2} - 2x + 1$

$(6x - 2a)(4 - 3x) = \frac{2 {a}^{2}b + 4a {b}^{2} }{2a} \\ 2(3x - a)(4 - 3x) = \frac{2ab(a + b)}{2a} \\ 2(3x - a)(4 - 3x) = b(a + b) \\ 24x - 18 {x}^{2} - 8a + 6ax = ab + {b}^{2}$