Question

упростите а:√75а-√48а+√300а
б: √
2√2+√32-2√200​

Answer 1

Ответ:

$11\sqrt{3a}\\\\-14\sqrt{2}$

Объяснение:

$\sqrt{75a}-\sqrt{48a}+\sqrt{300a}=\sqrt{25\cdot 3a}+\sqrt{16\cdot 3a}+\sqrt{100\cdot 3a}=\\\\5\sqrt{3a}-4\sqrt{3a}+10\sqrt{3a}=11\sqrt{3a}\\\\\\2\sqrt2+\sqrt{32}-2\sqrt{200}=2\sqrt2+\sqrt{16\cdot 2}-2\sqrt{100\cdot 2}=\\\\2\sqrt2+4\sqrt{2}-2\cdot 10\sqrt{2}=6\sqrt2-20\sqrt{2}=-14\sqrt{2}$