Question

6) (4x-3)²+(3x + 2)² > (5x+1)²

Answer 1

Ответ:

${(4x)}^{2} - 4x \times 3 \times 2 + {3}^{2} + {(3x)}^{2} + 3x \times 2 \times 2 + {2}^{2} > {(5x)}^{2} + 1 \times 5x \times 2 + 1$

${16x}^{2} - 24x + 9 + {9x}^{2} + 12x + 4 - {25x}^{2} - 10x - 1 > 0$

$- 22x + 12 > 0$

$- 11x + 6 > 0$

$11x - 6 < 0$

$11x < 6$

$x < \frac{6}{11}$