Question

3x(x^2-4x+3)=
-2b(b^2+2b-3)=
3c^2(-2c^4+c^2+3)=
(-3n^2+2n)•2n=
(2a^2-2a-5)•(-3a)=
помогите пжжжж

Answer 1

Ответ:

$3x(x {}^{2} - 4x + 3) = \\ = 3x {}^{3 } - 12x {}^{2} + 9x$

$- 2b(b {}^{2} + 2b - 3) = \\ = - 2b {}^{3} - 4b {}^{2} + 6b$

$3c {}^{2} ( - 2c {}^{4} + c {}^{2} + 3) = \\ = - 6c {}^{6} + 3c {}^{4} + 9c {}^{2}$

$( - 3n {}^{2} + 2n) \times 2n = \\ = - 6n {}^{3} + 4n {}^{2}$

$(2a {}^{2} - 2a - 5) \times ( - 3a) = \\ = - 6a {}^{3} + 6a {}^{2} + 15a$