Question

${x}^{3} + 3x {}^{2} - 4x - 12 > 0$
решите пожалуйста ​

Answer 1

$\displaystyle\bf\\x^{3} +3x^{2} -4x-12 > 0\\\\(x^{3} +3x^{2} )-(4x+12) > 0\\\\x^{2} \cdot(x+3)-4\cdot(x+3) > 0\\\\(x+3)\cdot(x^{2} -4) > 0\\\\(x+3)\cdot(x+2)\cdot(x-2) > 0\\\\\\- - - - - (-3)+ + + + + (-2)- - - - - (2)+ + + + + \\\\\\Otvet \ : \ x\in(-3 \ ; \ -2)\cup(2 \ ; \ + \infty)$