Question

даю 100 б заранее спасибо ​

Answer 1

Ответ:

1 Б

2 Д

3 A

4 В

Объяснение:

$C=\left(\frac{x_A+x_B}{2};\frac{y_A+y_B}{2}\right)$

$1\\\\A=\left(-3,4\right)\\\\B=\left(-1,2\right)\\\\C=\left(\frac{-3-1}{2};\frac{4+2}{2}\right)\\\\C=\left(\frac{-4}{2};\frac{6}{2}\right)\\\\C=\left(-2;3\right)$                       $2\\\\A=\left(-4,0\right)\\\\B=\left(0,4\right)\\\\C=\left(\frac{-4+0}{2};\frac{0+4}{2}\right)\\\\C=\left(\frac{-4}{2};\frac{4}{2}\right)\\\\C=\left(-2;2\right)$

$3\\\\A=\left(-6,5\right)\\\\B=\left(2,2\right)\\\\C=\left(\frac{-6+2}{2};\frac{5+2}{2}\right)\\\\C=\left(\frac{-4}{2};\frac{7}{2}\right)\\\\C=\left(-2;3,5\right)$                        $4\\\\A=\left(1,-5\right)\\\\B=\left(-5,1\right)\\\\C=\left(\frac{1-5}{2};\frac{-5+1}{2}\right)\\\\C=\left(\frac{-4}{2};\frac{-4}{2}\right)\\\\C=\left(-2;-2\right)$