Предмет: Геометрия, автор: forqiqi0

Промінь ОЅ лежить між сторонами кута АОВ, AOB=100°. Знайдіть кути AOS i BOS, якшо ZАOS-Z BOS=30°.
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Ответы

Автор ответа: nika46283
1
Звісно, ось коротка відповідь:

AOS = 80°
BOS = -30° (або можливо ви маєте на увазі 30°, якщо BOS не може бути від'ємним у вашому контексті).
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