Question

ПОМОГИТЕ СРОЧНО ДАЮ 100 БАЛОВ!!!!!!!!!!

Answer 1

Ответ:

Поделить почленно числитель на знаменатель .

$\displaystyle \bf a\ne 0\ ,\ \ \frac{a+2}{a}=\frac{a}{a}+\frac{2}{a}=1+\frac{2}{a}\\\\\\b\ne 0\ \ ,\ \ \frac{b-5}{b}=\frac{b}{b}-\frac{5}{b}=1-\frac{5}{b}\\\\\\x\ne 0\ ,\ \ \frac{3x+x^3}{x^2}=\frac{3x}{x^2}+\frac{x^3}{x^2}=\frac{3}{x}+x\\\\\\y\ne 0\ ,\ \ \frac{7y-y^4}{y^3}=\frac{7y}{y^3}-\frac{y^4}{y^3}=\frac{7}{y^2} -y\\\\\\m\ne 0\ ,\ \ \frac{12m-3m^6+9m^4}{3m^4}=\frac{12m}{m^4}-\frac{3m^6}{m^4}+\frac{9m^4}{m^4}=\frac{12}{m^3}-3n^2+9$  

$\displaystyle \bf n\ne 0\ ,\ \ \frac{6n^8-4n^5-2n^3}{2n^5}=3n^3-2-\frac{1}{n^2}\\\\\\a\ne -2b\ ,\ \ \frac{20(a+2b)^5-4(a^2+4ab+4b^2)}{20(a+2b)^2}= \frac{20(a+2b)^5-4(a+2b)^2}{20(a+2b)^2}=\\\\\\=(a+2b)^3-\frac{1}{5}\\\\\\y\ne 3x\ ,\ \frac{7(3x-y)^4-70(9x^2-6xy+y^2)}{35(3x-y)^2}=\frac{7(3x-y)^4-70(3x-y)^2}{35(3x-y)^2}=\\\\\\=\dfrac{1}{5}\, (3x-y)^2-2$