Question

СРОЧНО ДАЮ 100 БАЛОВ
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Answer 1

Ответ:

Ответ внизу)

Объяснение:

N0.1

$\left \{ {{x+2y=1} \atop {2x+y^{2}=-1 }} \right. \\\left \{ {{x=1-2y} \atop {2x+y^{2}=-1 }} \right. \\2(1-2y)+y^{2} =-1\\2-4y+y^{2} +1=0\\y^{2} -y-3y+3=0\\(y-1)(y-3)=0\\y-1=0\\y-3=0\\y_{1}=1\\ y_{2} =3$

$x=1-2*1\\x=1-2*3\\x_{1} =-1\\x_{2} =-5\\(x_{1} ,y_{1})=(-1,1)\\(x_{2},y_{2}=(-5,3)$

N0.2

Уравнение к задаче:

$\left \{ {{x+y=15} \atop {x^{2} +y^{2}=125 }} \right. \\\left \{ {{x=15-y} \atop {{x^{2} +y^{2}=125}} \right. \\(15-y)^{2} +y^{2} =125\\225-30y+y^{2}+y^2 =125\\225-30y+2y^{2}-125=0\\y^{2} -15y+50=0 \\y^{2}-5y-10y+50=0\\y(y-5)-10(y-5)=0\\(y-5)(y-10)=0\\y=5\\y=10$

$x=15-5=10\\x=15-10=5\\(x_{1},y_{1})=(10,5)\\(x_{2},y_{2})=(5,10)$