Question

спростить вираз 2y-4+2y²/y-4-y+4+16-y2 помогите даю 50б​

Answer 1

Ответ:

$\frac{4}{y-4}$

Объяснение:

$\frac{2y}{y-4}-\frac{4}{y+4}+\frac{2y^2}{16-y^2}=\frac{2y}{y-4}-\frac{4}{y+4}-\frac{2y^2}{y^2-16}=\\\\\frac{2y}{y-4}-\frac{4}{y+4}-\frac{2y^2}{(y-4)(y+4)}=\frac{2y(y+4)}{(y-4)(y+4)}-\frac{4(y-4)}{(y-4)(y+4)}-\frac{2y^2}{(y-4)(y+4)}=\\\\\frac{2y(y+4)-4(y-4)-2y^2}{(y-4)(y+4)}=\frac{2y^2+8y-4y+16-2y^2}{(y-4)(y+4)}=\\\\\frac{4y+16}{(y-4)(y+4)}=\frac{4(y+4)}{(y-4)(y+4)}=\frac{4}{y-4}$