Question

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Answer 1

Ответ:

1)

$( - \frac{1}{2} x {}^{8} y {}^{9} ) {}^{5} = \frac{( - 1x {}^{8} y {}^{9} ) {}^{5} }{2 {}^{5} } = \\ = \frac{ - x {}^{40} y {}^{45} }{32} = \\ = - \frac{x {}^{40} y {}^{45} }{32}$

2)

$2 \frac{1}{4} b {}^{2} c {}^{5} d {}^{3} \times \\ \times ( - 3 \frac{1}{3} b {}^{3} c {}^{4} d {}^{7} ) = \\ = \frac{9}{4} b {}^{2} c {}^{5} d {}^{3} \times ( - \frac{10}{3} b {}^{3} c {}^{4} d {}^{7} ) = \\ = - \frac{9 \times 10}{4 \times 3} b {}^{2 + 3} c {}^{5 + 4} d {}^{3 + 7} = \\ = - \frac{15}{2} b {}^{5} c {}^{9} d {}^{10}$

3)

$( - \frac{1}{2} ab) {}^{4 } \times (4a {}^{6} ) {}^{2} = \\ = \frac{ {a}^{4}b {}^{4} }{2 {}^{4} } \times 4 {}^{2} a {}^{12} = \\ = \frac{16a {}^{16}b {}^{4} }{16} = \\ = a {}^{16} b {}^{4}$