Question

log1/2(2x+1)>-2
log1/2(3-5x)<-3

Answer 1

$log_{frac{1}{2}}(2x+1)>-2$
$0<frac{1}{2}<1$
$0<2x+1<(frac{1}{2})^{-2}$
$0<2x+1<4$
$-1<2x<3$
$-0.5<x<1.5$
x є $(-0.5;1.5)$
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$log_{frac{1}{2}}(3-5x)<-3$
$0<frac{1}{2}<1$
$3-5x>(frac{1}{2})^{-3}$
$3-5x>8$
$-5x>5$
$x<-1$
x є $(-infty;-1)$