Предмет: Физика, автор: naroznijroma5

Наскільки градусів нагрієються 30 кг алюмінію при затраті 4,6 М ДЖ?

Ответы

Автор ответа: Аноним
0

Ответ:

Для розрахунку температурного зміщення можна використати формулу:

\[Q = m \cdot c \cdot \Delta T,\]

де:

- \(Q\) - теплова енергія (в Дж)

- \(m\) - маса (в кг)

- \(c\) - специфічна теплоємність матеріалу (в Дж/(кг·°C))

- \(\Delta T\) - зміна температури (в °C)

У вас є \(m = 30\) кг, \(Q = 4,6\) МДж (що дорівнює \(4,6 \times 10^6\) Дж).

Для алюмінію, специфічна теплоємність \(c\) приблизно 900 Дж/(кг·°C).

Тепер можемо підставити значення у формулу і вирішити для \(\Delta T\):

\[4,6 \times 10^6 = 30 \cdot 900 \cdot \Delta T.\]

Після вирішення цього рівняння, отримаємо зміну температури \(\Delta T\).

Объяснение:

Дельта позначається трикутником без слешів

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