Question

помогите пжпжжпжпжп даю 50 балов​

Answer 1

1.

1. $\sqrt{132} =\sqrt{4*33} = 2\sqrt{33}$
2. $\sqrt{252} = \sqrt{36*7} = 6\sqrt{7}$
3. $\sqrt{19a^{2}b^{2} } =\sqrt{19} ab$

2.

1. $13\sqrt{3} =\sqrt{3*13^{2} } =\sqrt{3*169} = \sqrt{507}$
2. $20\sqrt{2} = \sqrt{20^{2}*2} = \sqrt{800}$
3. $5cd\sqrt{7c} = \sqrt{5^{2}*7c^{3}d^{2} } =\sqrt{175c^{3}d^{2}}$

3.

$4\sqrt{44} - 5\sqrt{99} +2\sqrt{11} = 4\sqrt{4*11} - 5\sqrt{9 *11} +2\sqrt{11} = 8\sqrt{11}-15\sqrt{11}+2\sqrt{11} = -5\sqrt{11}$

$...=(\sqrt{7} - \sqrt{4*7} )*\sqrt{7} - (3\sqrt{10} -2\sqrt{4*10} )*\sqrt{10} = \\(\sqrt{7} - 2\sqrt{7} )*\sqrt{7} - (3\sqrt{10} -4\sqrt{10} )*\sqrt{10}=\\-\sqrt{7} *\sqrt{7} -(-\sqrt{10} )*\sqrt{10} = \\-7 + \sqrt{10} *\sqrt{10} = -7+10 = 3$

4.

1. $10 \sqrt{2} =20\sqrt{\frac{1}{2}}$
2. $0,6\sqrt{2} > 0,3\sqrt{5}$

$10 \sqrt{2} =20\sqrt{\frac{1}{2}}\\20\sqrt{\frac{1}{2}}=\sqrt{\frac{1}{2}*400} =\sqrt{\frac{400}{2}} = \sqrt{200} = \sqrt{2*100} = 10\sqrt{2}$

$0,6\sqrt{2} > 0,3\sqrt{5}\\\\0,6\sqrt{2} = \sqrt{2*0,6^{2} } = \sqrt{2*0,36 }=\sqrt{0,72} \\\\0,3\sqrt{5} = \sqrt{5*0,09} =\sqrt{0,45}$