Question

0.21. Решите уравнение: (DD) (S 1) 1,2x²+x=0 2) 1,6x-x²=0; 4) 5r=r; 5) 1,6x²=3x; 3) 0,5r-z=0; 6) x=x².​

Answer 1

0.21. Решите уравнение:

$1)1.2 {x}^{2} + x = 0$

$\frac{6}{5} x {}^{2} + x = 0$

$6x {}^{2} + 5x = 0$

$x \times (6x + 5) = 0$

$x = 0 \\ 6x + 5 = 0$

$x = 0 \\ x = - \frac{5}{6}$

$Ответ:x _1 = - \frac{5}{6} ,x_2 = 0$

$2)1.6x - x {}^{2} = 0$

$\frac{8}{5} x - x {}^{2} = 0$

$8x - 5x {}^{2} = 0$

$x \times (8 - 5x) = 0$

$x = 0 \\ 8 - 5x = 0$

$x = 0 \\ x = \frac{8}{5}$

$Ответ:x_1 = 0 ,x_2 = \frac{8}{5}$

$3)0.5r - z = 0$

$- z = - 0.5r$

$Ответ:= 0.5r$

$4)5r = r$

$5r - r = 0$

$4r = 0$

$Ответ:r = 0$

$5)1.6 {x}^{2} = 3x$

$\frac{8}{5} {x}^{2} = 3x$

$\frac{8}{5} {x}^{2} - 3x = 0$

$x \times ( \frac{8}{5} x - 3) = 0$

$x = 0 \\ \frac{8}{5} x - 3 = 0$

$x = 0 \\ x = \frac{15}{8}$

$Ответ:,x _{1} = 0,x _{2} = 1.875$

$6)x = x {}^{2}$

$x - x {}^{2} = 0$

$x \times (1 - x) = 0$

$x = 0 \\ 1 - x = 0$

$x = 0 \\ x = 1$

$Ответ:x _{1}= 0 ,x _{2} = 1$