Предмет: Алгебра, автор: tgtgyfdnhbg12

Розв'язати системи рівнянь трьома способами (Повне розв'язування, з графіками).​

Приложения:

Ответы

Автор ответа: desiatnik13
1
1)(у,х)=(-2,-3). 2)(у,х)= (3,0).
Приложения:
Автор ответа: ludmilaksenija2005
0

Объяснение:

метод сложения

{x+y= -5

{4x-y= -5

+ ————

5х= -10

х= -10:5

х= -2

-2+у= -5

у= -5+2

у= -3

(-2 ; -3)

метод подстановки:

{х+у= -5 х= -5-у

{4х-у= -5

4•(-5-у)-у= -5

-20-4у-у= -5

-5у= -5+20

-5у=15

у=15:(-5)

у= -3

х= -5-(-3)

х= -5+3

х= -2

(-2 ; -3)

графический метод:

{х+у= -5

{4х-у= -5

х+у= -5

у= -5-х синяя

таблица:

х 0 1

у -5 -6

4х-у= -5

у=4х+5 красная

таблица :

х 0 1

у 5 9

решение: точка пересечения:( -2 ; -3)

2.

метод сложения:

{2х+3у=6

{3х-у=9 •3

{2х+3у=6

{9х-3у=27

+ ————

11х=33

х=33:11

х=3

2•3+3у=6

6+3у=6

3у=6-6

3у=0

у=0

(3;0)

метод подстановки:

{2х+3у=6

{3х-у=9 у=3х-9

2х+3(3х-9)=6

2х+9х-27=6

11х=6+27

11х=33

х=33:11

х=3

у=3•3-9

у=9-9

у=0

(3; 0)

графический метод:

{2х+3у=6

{3х-у=9

2х+3у=6

3у=6-2х

у=2-2/3•х синяя

таблица:

х 0 3

у 2 0

3х-у=9

у=3х-9 красная

таблица:

х 0 1

у 9 -6

решение: точка пересечения: (3 ; 0)

Приложения:
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