Question

Нужно решить как на примере 5 задач.Даю 100 балов.Срочнооооо​

Answer 1

Ответ:

Объяснение:

1)

CO2

w(C) = 12/44 * 100% = 27,27%

w(O) = 100% - 27,27% = 72,73%

NaOH

w(Na) = 23/40 * 100% = 57,5%

w(O) = 16/40 * 100% = 40%

w(Н) = 100% - 57,5% - 40% = 2,5%

СаСО3

w(Сa) = 40/100 * 100% = 40%

w(С) = 12/100 * 100% = 12%

w(О) = 100% - 40% - 12% = 48%

Zn(OH)2

w(Zn) = 65/99 * 100% = 65,65%

w(O) = 32/99 * 100% = 32,32%

w(H) = 100% - 65,65% - 32,32% = 2,03%

Al2(SO4)3

w(Al) = 54/342 * 100% = 15,8%

w(S) = 96/342 * 100% = 28,1%

w(O) = 100% - 15,8% - 28,1% = 56,1%