Question

допоможіть будь ласка​

Answer 1

$\displaystyle\bf\\f(x)=\left \{ {{-x^{2} +4 \ \ , \ \ x < 1 } \atop {x-3 \ \ , \ \ x\geq 1}} \right. \\\\\\1)\\\\-2 < 1 \ \ \Rightarrow \ \ f(-2)=-(-2)^{2} +4=-4+4=0\\\\2)\\\\0 < 1 \ \ \Rightarrow \ \ f(0)=-0^{2} +4=4\\\\3)\\\\1=1 \ \ \Rightarrow \ \ f(1)=1-3=-2\\\\4)\\\\-3 < 1 \ \ \Rightarrow \ \ f(-3)=-(-3)^{2} +4=-9+4=-5$