Question

25-4y² первой
Второй 36m²-49n²
Третий a²b²-81
Четвертый 100m⁶-1
Это все спасибо

Answer 1

$25 - 4 {y}^{2} = {5}^{2} - {2}^{2} {y}^{2} = {5}^{2} - (2y {)}^{2} = (5 - 2y) \times (5 + 2y)$

$36 {m}^{2} - 49 {n}^{2} = {6}^{2} {m}^{2} - {7}^{2} {n}^{2} = (6m {)}^{2} - (7n {)}^{2} = (6m - 7n) \times (6m + 7n)$

${a}^{2} {b}^{2} - 81 = (ab {)}^{2} - {9}^{2} = (ab - 9) \times (ab + 9)$

$100 {m}^{6} - 1 = {10}^{2} m^{2 \times 3} - {1}^{2} = {10}^{2} \times ( {m}^{3} {)}^{2} - {1}^{2} = (10 {m}^{3} {)}^{2} - {1}^{2} = ( {10m}^{3} - 1) \times (10m^{3} + 1)$

НЕ ЗА ЧТО!